Contents
Question 1
For the following circuit, find (a) the value of the current I, (b) the value of the voltage across each resistor, and (c) the power absorbed or produced in each element.
% Initial Information R1 = 400; R2 = 180; R3 = 620; Vi = 12; % a - the value of the current I I = Vi/(R1+R2+R3); fprintf('a) Current I: %g\n',I); % b - the value of the voltage across each resistor V1 = I*R1; V2 = I*R2; V3 = I*R3; fprintf('b) Voltage across Resistor 1: %g\n',V1); fprintf(' Voltage across Resistor 2: %g\n',V2); fprintf(' Voltage across Resistor 3: %g\n',V3); % c - the power absorbed or produced by each element P1 = (I^2)*R1; P2 = (I^2)*R2; P3 = (I^2)*R3; fprintf('c) Power absorbed by R1: %g\n',P1); fprintf(' Power absorbed by R2: %g\n',P2); fprintf(' Power absorbed by R3: %g\n',P3);
a) Current I: 0.01 b) Voltage across Resistor 1: 4 Voltage across Resistor 2: 1.8 Voltage across Resistor 3: 6.2 c) Power absorbed by R1: 0.04 Power absorbed by R2: 0.018 Power absorbed by R3: 0.062
Question 2
Find the value of the current I flowing into the node.
% Initial Information (positive means going into the node, negative leaving % the node) I1 = -60; I2 = 140; I3 = -30; % Value of current I I = -1*(I1+I2+I3); fprintf('Value of current I: %g\n',I);
Value of current I: -50
Question 3
Determine the current flowing through and the voltage across each resistor in the following circuit. Also determine the equivalent resistance of the circuit.
% Initial Information Vi = 48; R1 = 100; R2a = 480; R2b = 480; R2c = 480; R3a = 50; R3b = 200; % Equivalent resistance of parallel resistors: R2 = (1/R2a)+(1/R2b)+(1/R2c); R2 = 1/R2; R3 = (1/R3a)+(1/R3b); R3 = 1/R3; % Value of Current I: I = Vi/(R1+R2+R3); % Resistor 1: % Current flowing through: I1 = I; % Voltage across: V1 = I1*R1; fprintf('R1 - Current: %g\n',I1); fprintf('R1 - Voltage: %g\n',V1); % Resistors 2: % Current flowing through: I2a = (Vi-V1)/(R2a); I2b = (Vi-V1)/(R2b); I2c = (Vi-V1)/(R2c); % Voltage across: I2 = I; V2 = I2*R2; V2a = V2; V2b = V2; V2c = V2; fprintf('R2a - Current: %g\n',I2a); fprintf('R2a - Voltage: %g\n',V2a); fprintf('R2b - Current: %g\n',I2b); fprintf('R2b - Voltage: %g\n',V2b); fprintf('R2c - Current: %g\n',I2c); fprintf('R2c - Voltage: %g\n',V2c); % Resistors 3: % Current flowing through: I3a = (Vi-V1-V2)/(R3a); I3b = (Vi-V1-V2)/(R3b); % Voltage across: I3 = I; V3 = I3*R3; V3a = V3; V3b = V3; fprintf('R3a - Current: %g\n',I3a); fprintf('R3a - Voltage: %g\n',V3a); fprintf('R3b - Current: %g\n',I3b); fprintf('R3b - Voltage: %g\n',V3b); %Equivalent Resistance: Rs = R1+R2+R3; fprintf('Equivalent Resistance: %g\n',Rs);
R1 - Current: 0.16 R1 - Voltage: 16 R2a - Current: 0.0666667 R2a - Voltage: 25.6 R2b - Current: 0.0666667 R2b - Voltage: 25.6 R2c - Current: 0.0666667 R2c - Voltage: 25.6 R3a - Current: 0.128 R3a - Voltage: 6.4 R3b - Current: 0.032 R3b - Voltage: 6.4 Equivalent Resistance: 300